49x^2-64x=0.

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Solution for 49x^2-64x=0. equation: 



49x^2-64x=0.

a = 49; b = -64; c = 0;
Δ = b2-4ac
Δ = -642-4·49·0
Δ = 4096
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{4096}=64$


$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-64)-64}{2*49}=\frac{0}{98}
=0
$


$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-64)+64}{2*49}=\frac{128}{98}
=1+15/49
$

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